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Multiple Choice

A vertical column of water 2.31 feet high exerts what pressure in psi at the base?

To determine the pressure exerted by a vertical column of water at its base, you can use the formula for hydrostatic pressure: \[ P = h \times \rho \times g \] where: - \( P \) is the pressure in pounds per square foot (psf), - \( h \) is the height of the water column in feet, - \( \rho \) is the density of water (approximately 62.4 pounds per cubic foot), - \( g \) is the acceleration due to gravity (which is embedded in the weight of water). For practical purposes, a simplified version of the formula for pressure in psi can be used, which states that 1 foot of water column generates approximately 0.433 psi at the base. Thus, for a height of 2.31 feet: \[ P = 2.31 \, \text{feet} \times 0.433 \, \text{psi/foot} \] Calculating this: \[ P = 2.31 \times 0.433 \approx 1.0 \, \text{psi} \] This calculation confirms that a vertical column of water 2.31 feet high exerts approximately

To determine the pressure exerted by a vertical column of water at its base, you can use the formula for hydrostatic pressure:

[ P = h \times \rho \times g ]

where:

  • ( P ) is the pressure in pounds per square foot (psf),

  • ( h ) is the height of the water column in feet,

  • ( \rho ) is the density of water (approximately 62.4 pounds per cubic foot),

  • ( g ) is the acceleration due to gravity (which is embedded in the weight of water).

For practical purposes, a simplified version of the formula for pressure in psi can be used, which states that 1 foot of water column generates approximately 0.433 psi at the base.

Thus, for a height of 2.31 feet:

[ P = 2.31 , \text{feet} \times 0.433 , \text{psi/foot} ]

Calculating this:

[ P = 2.31 \times 0.433 \approx 1.0 , \text{psi} ]

This calculation confirms that a vertical column of water 2.31 feet high exerts approximately